For the reaction ${\mathrm{X}}_{\left(\mathrm{s}\right)}\rightleftharpoons {\mathrm{Y}}_{\left(\mathrm{s}\right)}+{\mathrm{Z}}_{\left(\mathrm{g}\right)},\mathrm{the} \mathrm{plot} \mathrm{of} \mathrm{the} \ln \frac{{\mathrm{p}}_2}{{\mathrm{p}}^0} \mathrm{versus} \frac{{10}^4}{\mathrm{T}}$ is given below (in solid line),where  p₂ is the ‘p’ (in bar) of the gas ‘z’ at temperature ‘T’ and p° =1 bar ?

(Given $\frac{\mathrm{d}(\ln \mathrm{k})}{{\mathrm{d}}^{\left(\frac{1}{\mathrm{T}}\right)}}=\frac{-{\mathrm{\Delta H}}^0}{\mathrm{R}}$,where the equilibrium constant,k $\frac{{\mathrm{p}}_2}{{\mathrm{p}}^0}$and the gas constant, $\mathrm{R}=8.314{\mathrm{Jk}}^{-1}{\mathrm{mol}}^{-1}$ )