For the reaction $2 A \to B$ the concentration of ‘A’ decreases from 1M to 0.1M in 10 minutes. Rate of disappearance of ‘A’ is equal to

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$0.18 M \min^{- 1}$

$0.045 M \min^{- 1}$

$0.09 M \min^{- 1}$

$0.01 M \min^{- 1}$

answer is C.

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Detailed Solution

$Rate = - \frac{1}{2} \frac{d [A]}{dt} = + \frac{d [B]}{dt}; Rate of disappearance of' A' will be - \frac{d [A]}{dt} = \frac{(1 - 0.1) M}{10 minutes} = 0.09 M \min^{- 1};$

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