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Q.

 For the reaction, 2H2+O2→2H2O, : ΔH = – 571kJ ; Bond energy of (H–H) = 435 kJ and (O=O) =498kJ ,  the average bond energy of O–H bond using the above data is

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a

484kJ

b

–84kJ

c

271kJ

d

– 271kJ

answer is A.

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Detailed Solution

\begin{array}{l} {\Delta _r}(H) = \sum B{E_{reac\tan ts}} - \sum B{E_{products}}\\ - 571KJ = [2B{E_{H - H}} + B{E_{O = O}}] - [4B{E_{O - H}}]\\ - 571 = [2(435) + 498] - [4B{E_{O - H}}]\\ - 571 = 1368 - 4B{E_{O - H}}\\ B{E_{O - H}} = \frac{{1939KJ}}{4} = 484.75KJ \end{array}

 

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