Q.

For the reaction: 2NO2(g)N2O4(g);ΔH<0

What predictions can be made about the sign of ΔS and the temperature conditions under which the reaction would be spontaneous?

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a

ΔSrxnTemperature Condition
positivehigh temperature

b

ΔSrxnTemperature Condition
negativelow temperature

c

ΔSrxnTemperature Condition
negativehigh temperature

d

ΔSrxnTemperature Condition
positivelow temperature

answer is C.

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Detailed Solution

Given reaction is,

2NO2(g)N2O4(g);ΔH<0

Here, enthalpy is positive. When the temperature is increases, the change in entropy also increased.

Thus, ΔSrxn is positive at high temperature.

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