For the reaction $A + 2 B \to 2 C$ . The value of equilibrium constant is 100 at 298K. If the initial concentration of all the three species is 1M each, then the equilibrium concentration of C is x × $10^{- 1} M$ . The value of x is (Nearest integer)

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answer is 25.

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Detailed Solution

$A + 2 B \to 2 C I n i t i a l 1 1 1 E q n 1 - x 1 - x 1 + 2 x K_{C} = \frac{{[C]}^{2}}{[A] [B]} 100 = \frac{{[1 + 2 x]}^{2}}{[1 - x] [1 - x]} x = \frac{3}{4} C \to 1 + 2 x = 1 + 2 \times \frac{5}{4} = 25 \times 10^{1}$

Hence, the correct option 25.

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