For the reaction $A+2B+3C⟶D$, following data was obtained, Using the data, calculate order of the reaction.

Exp.	Concentration (M}			Rate of reaction M sec-1
	[A]	[B]	[C]
1	0.6	1.2	0.3	0.5
2	0.6	2.4	0.3	1
3	1.2	2.4	0.3	2
4	0.6	1.2	0.9	4.5

Given reaction is,

$A+2B+3C⟶D$, 

Here, the from experiment 1 to 2, when the concentration of A and C remain constant and value of B is halved, then the value of rate is also halved. The order in this case for the reaction is 4.