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For the reaction, $A + B ⇌ C + D,$ the initial concentration of A and B are equal, but the equilibrium concentration of C is twice that of equilibrium concentration of A. The equilibrium constant is:

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Detailed Solution

$\underset{(a - x)}{\underset{a}{A}} + \underset{(a - x)}{\underset{a}{B}} ⇌ \underset{x}{\underset{0}{C}} + \underset{x}{\underset{0}{D}}$

Given, x = 2(a- x)
$K_{c} = \frac{x^{2}}{(a - x)^{2}} = \frac{{[2 (a - x)]}^{2}}{{(a - x)}^{2}} = 4$

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