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Q.

For the reaction H2(g)+Br2(g)⟶2HBr(g) the experimental data suggested that r=kH2Br21/2 The molecularity and order of the reaction are respectively :

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a

1,12

b

2,32

c

32,32

d

not defined 32

answer is A.

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Detailed Solution

The molecularity and order of the reaction,

H2(g)+Br2(g)→2HBr(g)

r=kH2Br21/2

Molecularity=2

Order =1+0.5

=1.5 =3/2

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