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For the reaction,
$I_{2} (g) ⇌ 2 I (g); K_{C} = 37.6 \times 10^{- 6}$
at 1000 K. If 1.0 mole of $I_{2}$ ir introduced into a 1.0 L flask at 1000 K, at equilibrium

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$[I_{2}] < [I]$

$[I_{2}] > [I]$

Unpredictable

$[I_{2}] = [I]$

answer is A.

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Detailed Solution

$As K_{C} is very low and K_{C} = \frac{[I]^{2}}{[I_{2}]}$

$∴ [I_{2}] > [I]$

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