For the reduction of ${\mathrm{NO}}_3^{-}$ ion is an aqueous solution, E° is +0.96V. Values of E° for some metal ions are given below:

$\begin{array}{l}{\mathrm{V}}_{(\mathrm{aq}.)}^{2+}+2{\mathrm{e}}^{-}⟶\mathrm{V};\hspace{0.25em}\hspace{0.25em}\hspace{0.25em}\hspace{0.25em}{\mathrm{E}}^{\circ }=-1.19\mathrm{V}\\ {\mathrm{Fe}}_{(\mathrm{aq}.)}^{3+}+3{\mathrm{e}}^{-}⟶\mathrm{Fe};\hspace{0.25em}\hspace{0.25em}\hspace{0.25em}\hspace{0.25em}{\mathrm{E}}^{\circ }=-0.04\mathrm{V}\\ {\mathrm{Au}}_{(\mathrm{aq}.)}^{3+}+3{\mathrm{e}}^{-}⟶\mathrm{Au};\hspace{0.25em}\hspace{0.25em}\hspace{0.25em}\hspace{0.25em}{\mathrm{E}}^{\circ }=+1.40\mathrm{V}\\ {\mathrm{Hg}}_{(\mathrm{aq}.)}^{2+}+2{\mathrm{e}}^{-}⟶\mathrm{Hg};\hspace{0.25em}\hspace{0.25em}\hspace{0.25em}\hspace{0.25em}{\mathrm{E}}^{\circ }=+0.86\mathrm{V}\end{array}$

The pair(s) of metals that is (are) oxidized by ${\mathrm{NO}}_3^{-}$ in aqueous solution is (are):