For the resistance network shown in the figure, choose the correct option(s).

P and Q and S and T are at same potential as circuit is symmetric.

$$\begin{gathered} I_2=\frac{12}{2+2+2}=2A \\ {I}_3=\frac{12}{4+4+4}=1A \\ {I}_1=I_2+I_3=3Aand{I}_{PQ}=0(V_P=V_Q) \\ {V}_{MS}=4\times 2=8V \\ {V}_{NQ}=4\times 1=4V \\ \Rightarrow V_P<V_Q \end{gathered}$$