For the same metal, stabilization energies of tetrahedral and octahedral complexes are related as

 

It is given to find out for the same metal, how the stabilization energies of tetrahedral and octahedral complexes are related. 

The separation of five degenerate d-orbitals of the metal ion while interacting with ligands is called crystal field splitting. 

Explanation

The stabilization energy of octahedral complexes is greater than tetrahedral complexes. 

Because tetrahedral complex splitting is $\frac{2}{3}$ rd of an octahedral complex, thus the stabilization energy of tetrahedral complex for one ligand splitting is  $\frac{{∆}_0}{6}\left(\frac{2}{3}\right)$. 

Four and eight ligands approach the tetrahedral and octahedral complexes respectively.  

Then, for four more ligands, tetrahedral splitting is ${∆}_t=4\left(\frac{{∆}_0}{6}\right)\left(\frac{2}{3}\right)$

Hence the correct answer is D)