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Q.

For the same raise in temperature of two moles of gas at constant pressure, the heat required for triatomic gas is K times the heat required for  monoatomic gas. The value of K is

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a

32

b

52

c

83

d

85

answer is D.

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Detailed Solution

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molar specific heat of gas at constant pressure for tri atomic gas (6° of freedom)

Cp=4R

 

molar specific heat of gas at constant pressure is Cp Cp=52R for monoatomic gas

heat required for raise in temperature of gas at constant pressure is Q=nCp∆T

Qtriatomic=kQmonotomic substitute the values

n(4R)∆T=kn(5R2)T

 

K=4R52R=85

Heat required is 85  times.

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