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For the situation shown in Fig. in Column I, the statements regarding friction forces are mentioned, while in Column II some information related to friction forces are given. Match the entries of Column I with the entries of Column II.
Column–I Column–II
A Total friction force on 3 kg block is P towards right
B Total friction force on 5 kg block is Q towards left
C Fiction force on 2 kg block due to 3 kg block is R zero
D Friction force on 3 kg block due to 5 kg block is S non-zero

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$A - R, B - Q S, C - P R, D - Q S$

$A - Q S, B - R, C - P S, D - Q S$

$A - Q S, B - P R, C - R, D - Q S$

$A - Q S, B - R, C - Q S, D - P R$

answer is B.

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Detailed Solution

$f_{l_{1}} = 0.2 \times 2 g = 4 N f_{l_{2}} = 0.1 \times 5 g = 5 N f_{l_{3}} = 0.1 \times 10 g = 10 N$
Friction on 3 kg block is towards left and non-zero.
Hence (A) $\to$ q,s
$f_{l_{2}} < f_{l_{3}}$ hence 5 kg block will not move. So the net friction on 5 kg will be zero.
Hence (B) $\to$ r

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