For the situation shown in fig. mark the correct statements  

 

 

 

 

As no charge is present inside the conductor, potential at any point inside the conductor is same as that of potential of conductor. 

So, potential of conductor = potential at center  

$\begin{array}{l}=V_q+V_{\text{induced charges }}\\ V_{\text{conductor }}=\frac{q}{4\pi {\in }_0(d+R)}+0\end{array}$

as total induced charge at conductors surface is equal to 0, potential at center due to induced charge is also zero.

For point B 

$V_{\text{conductor }}=V_{\text{at point }B}=V_q+V_{\text{induced charges }}$

$V_{induced charge }=\frac{q}{4\pi {ϵ}_0(d+R)}-\frac{q}{4\pi {ϵ}_{0}d}=-\frac{qR}{4\pi {ϵ}_0(d+R)}$