For the situation shown in figure (assume r >> length of dipole), mark out the correct statement(s).

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For the situation shown in figure (assume r >> length of dipole), mark out the correct statement(s).

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Force acting on the dipole is zero.

Torque acting on the dipole is $pQ / 4 {πε}_{0} r^{2}$ in clockwise direction.

Force acting on the dipole is approximately $pQ / 4 {πε}_{0} r^{3}$ and is acting upward.

Torque acting on the dipole is $pQ / 4 {πε}_{0} r^{2}$ in anti-clockwise direction.

answer is B, C.

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Detailed Solution

The situation is shown in figure.

${\vec{F}}_{net} = 2 Fsin θ ↑= \frac{p Q}{4 {πε}_{0} r^{3}}$

$\overset{}{τ} = Fcos θ \times 2 a$

In clockwise direction $= \frac{p Q}{4 {πε}_{0} r^{2}}$

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