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For the situation shown in figure. (assume r> >length of dipole) mark the correct statements

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Force acting on the dipole is approximately $\frac{p Q}{4 π ϵ_{0} r^{3}}$ and acting upward

Force acting on the dipole is zero

Torque acting on dipole is $\frac{p Q}{4 π ϵ_{o} r^{2}}$ in CW direction

Torque acting on dipole is $\frac{p Q}{4 π ϵ_{0} r^{2}}$ in ACW direction

answer is B, C.

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Detailed Solution

The situation is shown in. figure.

$\begin{array}{l} {\vec{F}}_{net} = 2 Fsin θ ↑ \\ = \frac{pQ}{4 π ϵ_{0} R^{3}} \\ \vec{τ} = F \cos θ \times 2 a C W direction \\ = \frac{p Q}{4 π ϵ_{0} r^{2}} \end{array}$

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