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For the system shown in the figure, $m_{1} > m_{2} > m_{3} > m_{4}$ . Initially, the system is at rest in equilibrium condition. If the string joining m₄ and ground is cut, then just after the string is cut.
Statement I: $m_{1}, m_{2}, m_{3}$ remain stationary.
Statement II: The value of acceleration of all the four blocks can be determined.
Statement III: Only m₄ remains stationary.
Statement IV: Only m₄ accelerates.
Now, choose the correct options.

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All the statements are correct.

Only I, II, and IV are correct.

Only I and II are correct.

Only II and IV are correct.

answer is B.

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Detailed Solution

Before cutting the string, the tension in string joining m₄ and ground is $T = (m_{1} + m_{2} - m_{3} - m_{4}) g$

And the spring force in the spring joining $m_{3} and m_{4} is T + m_{4} g .$

As the string is cut, the spring forces do not change instantly, so just after cutting the string the equilibrium of $m_{1}, m_{2} and m_{3}$ , would be maintained but mass accelerates in upward direction with acceleration given by

$a = \frac{(m_{1} + m_{2} - m_{3} - m_{4}) g}{m_{4}}$

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