For the velocity - time graph shown in figure below the distance covered by the body in last two seconds of its motion is what fraction of the total distance covered by it in all the total distance covered by it in all the seven seconds

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$\frac{2}{3}$

$\frac{1}{2}$

$\frac{1}{4}$

$\frac{1}{3}$

answer is B.

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Detailed Solution

Area of triangle= 1/2 x base x height

Area of rectangle = length × breath

for seven seconds
$s_{1} = \frac{1}{2} \times 10 \times 20 + 10 \times 20 + \frac{1}{2} \times 10 \times 2; s_{1} = 40 m$

for last 2 seconds
$s_{2} = \frac{1}{2} \times 10 \times 2 = 10 m \frac{s_{1}}{s_{2}} = \frac{10}{40} = \frac{1}{4}$

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