For the velocity - time graph shown in figure below the distance covered by the body in last two seconds of its motion is what fraction of the total distance covered by it in all the total distance (in m) covered by it in all the seven seconds $\_\_\_\_\_\_$ × 10^–2

The distance covered is equal to the area under the velocity-time graph.

Distance in last two seconds s₂​ = 1/2​×8×2 = 8 m

Total distance = 1/2​ × 8 × (6+2) = 32 m

Fraction of the distance covered by the body in the last two seconds of its motion to the total distance traveled by it in all seven seconds is  8/32 = 1:4