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Q.

For three positive integers p, q, r, xpq2=yqr=zp2r and r=pq+1 such that 3, 3logy x,3logz y,7logx z are in A.P. with common difference 1/2. Then   r-p-q is equal to 

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a

6

b

2

c

12

d

-6

answer is B.

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Detailed Solution

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3logyx3=12x=y7/6pq=6 Also 3logzy3=1y=z4/34q=3p2 p=2,q=3,r=7 rpq=2

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