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Q.

For two Bohr orbits n1 and n2 which follow the relationships, n22n12=21 and n2n1=3

If an electron makes transition from n2 to n1 directly then :

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a

longest frequency of Lyman series is emitted

b

only one spectral line is emitted

c

third longest wavelength of Balmer series is emitted

d

longest frequency of Balmer series is emitted

answer is A, D.

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Detailed Solution

We have,

n2+n1=7

n2n1=3

 n2=5, n1=2  [3rd line of Balmer series]

So, option A and D are correct with these relations.
 

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