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For what value of k the pair of equations $k x − y = 2$ and $6 x − 2 y = 3$ has a unique solution.

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k ≠ 4

k ≠ 3

k ≠ 7

k ≠ 10

answer is B.

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Detailed Solution

According to the question we have

k x − y = 2, 6 x − 2 y = 3

Let us find the value of

k

For unique solution

a 1 a 2 ≠ b 1 b 2

Here,

a 1 = k, b 1 = − 1 a 2 = 6, b 2 = − 2

For unique solution

a 1 a 2 ≠ b 1 b 2 ⇒ k 6 ≠ − 1 − 2 ⇒ k ≠ 3

Thus, the final value is

k ≠ 3

.
Therefore, the correct option is 2.

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