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For which of the following reaction, $∆$ H = $∆$ E + 2RT ?

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$2 {SO}_{2 (g)} + O_{2 (g)} \overset{}{\to} 2 {SO}_{3 (g)}$

NH₄HS_(s) $\overset{}{\to}$ NH_3(g) + H₂S_(g)

N_2(g) + O_2(g) $\overset{}{\to}$ 2NO_(g)

PCl_5(g) $\overset{}{\to}$ PCl_3(g) + Cl_2(g)

answer is B.

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Detailed Solution

$∆ H = ∆ E + ∆ n_{g} RT {NH}_{4} HS (s) \to {NH}_{3} (g) + H_{2} S (g) ∆ n_{g} = no . of moles of gaseous products - no . of moles of gaseous reactants ∆ n_{g} = (1 + 1) - 0 = 2 ∆ H = ∆ E + 2 RT$

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