For which of the following reactions, Kp (RT)2 = Kc

H 2 ( g ) + I 2 ( g ) ⇔ 2 HI ( g )

H 2 ( g ) + I 2 ( g ) ⇔ 2 HI ( g )

N 2 ( g ) + 3 H 2 ( g ) ⇔ 2 NH 3 ( g )

H 2 ( g ) + I 2 ( g ) ⇔ 2 HI ( g )

PCl 5 ( g ) ⇔ PCl 3 ( g ) + Cl 2 ( g )

2 SO 2 ( g ) + O 2 ( g ) ⇔ 2 SO 3 ( g )

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For which of the following reactions, K_p (RT)² = K_c

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$N_{2 (g)} + 3 H_{2 (g)} \Leftrightarrow 2 {NH}_{3 (g)}$

$H_{2 (g)} + I_{2 (g)} \Leftrightarrow 2 {HI}_{(g)}$

${PCl}_{5 (g)} \Leftrightarrow {PCl}_{3 (g)} + {Cl}_{2 (g)}$

$2 {SO}_{2 (g)} + O_{2 (g)} \Leftrightarrow 2 {SO}_{3 (g)}$

answer is B.

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Relation between Kp and Kc is:

$K_{p} = K_{c} {(RT)}^{∆ n}$

From above expression:

$K_{p} {(RT)}^{2} = K_{c} K_{p} = K_{c} {(RT)}^{- 2}$

$∆ n = no of gaseous moles (product) - no of gaseous moles (reactant)$

Considering reaction present in option-b:

$∆ n = 2 - 4 = - 2$

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