For which of the following, the pH of solution is 11?
 

 Given data: It is given to find the pH of the solution.

Explanation:$Ba(OH{)}_2$ assuming it to be completely 
$BaO{H}_2\iff B{a}^{2+}+2O{H}_{aq}^{-}$
Since $BaO{H}_2$ is completely ionized, one mole of $BaO{H}_2$ gives 2 moles of $O{H}^{-}$ ions.
Therefore, $O{H}^{-}= 2 BaO{H}_2 = 2 \times 0.001=0.002M$
$$\begin{gathered} H_3{O}^{+}=\frac{K_w}{O{H}^{-}} \\ \frac{1\times {10}^{-14}}{0.002}=5\times {10}^{-12} \end{gathered}$$
$pH=-log\left[H_3{O}^{+}\right]=-log\left(5\times {10}^{-12}\right)=-log5+log{10}^{-12}$
$\left(0.699-12\right)=11.301$

Hence, the correct option is (D).