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For which of the following $K_{P}$ is less than $K_{C} ?$

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$N_{2} O_{4} ⇌ 2 {NO}_{2}$

$N_{2} + 3 H_{2} ⇌ 2 {NH}_{3}$

$H_{2} + I_{2} ⇌ 2 HI$

$CO + H_{2} O ⇌ {CO}_{2} + H_{2}$

answer is B.

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Detailed Solution

$N_{2} + 3 H_{2} ⇌ 2 {NH}_{3}$

$K_{P} = K_{C} {(RT)}^{∆ n} ∆ n = P_{mole} - R_{mole} ∆ n = (2 - 4) = - 2 K_{P} = K_{C} {(RT)}^{- 2} K_{P} < K_{C}$

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