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Q.

For x, let tan-1(x)-π2,π2. Then the minimum value of the function f: defined by f(x)=0xtan-1xe(t-cost)1+t2023dt is

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Detailed Solution

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fx=0xtan1xetcost1+t2023  dt
f'x=extan1xcosxtan1x1+xtan1x2023x1+x2+tan1x
Always non zero
f'x=0             x1+x2+tan1x=0
Question Image
At x=0 local min
(Or)
For x>0 (or) x<0  is +ve min  happened at x=0 only logically
f(0)=0

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For x∈ℝ, let tan-1(x)∈-π2,π2. Then the minimum value of the function f:ℝ→ℝ defined by f(x)=∫0xtan-1xe(t-cost)1+t2023dt is