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For $2 S O_{2} + O_{2} ⇌ 2 S O_{3}, H = - Q K J,$ as per Lechatelier's principle which of the
following changes favors forward reaction yielding more $S O_{3}$ ?
(A) Adding more $O_{2}$
(B) Removing $S O_{3}$
(C) Applying high $P$
(D) Change of catalyst

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A, B & D

A, B & C

A & D

A, B, C, & D

answer is D.

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Detailed Solution

Low temperature helps the process because it is exothermic. High pressure encourages reaction since it results in a decrease in the number of moles.

Therefore, the correct answer is an option (D) A, B & C.

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