Force and area are measured as 20 N and 5m2 with errors 0.05 N and 0.0125 m2. The maximum error in pressure is (SI unit)

P=FA⇒ΔPP=ΔFF+ΔAA⇒ΔP=PΔFF+ΔAA

Force and area are measured as 20 N and 5m2 with errors 0.05 N and 0.0125 m2. The maximum error in pressure is (SI unit)

P=FA⇒ΔPP=ΔFF+ΔAA⇒ΔP=PΔFF+ΔAA

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Force and area are measured as 20 N and 5m² with errors 0.05 N and 0.0125 m². The maximum error in pressure is (SI unit)

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4 ± 0.0625

4 ± 0.05

4 ± 0.125

4 ± 0.02

answer is D.

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$P = \frac{F}{A} \Rightarrow \frac{ΔP}{P} = \frac{ΔF}{F} + \frac{ΔA}{A} \Rightarrow ΔP = P (\frac{ΔF}{F} + \frac{ΔA}{A})$

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Force and area are measured as 20 N and 5m2 with errors 0.05 N and 0.0125 m2. The maximum error in pressure is (SI unit)

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Force and area are measured as 20 N and 5m² with errors 0.05 N and 0.0125 m². The maximum error in pressure is (SI unit)