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Force between two poles with unit pole strength placed at a distance of one metre is

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1 N

$\frac{10^{- 7}}{4 π} N$

$10^{- 7} N$

$4 π x 10^{- 7} N$

answer is C.

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Detailed Solution

$F = 10^{- 7} x \frac{m^{2}}{r^{2}} = \frac{10^{- 7} {(1)}^{2}}{{(1)}^{2}} = 10^{- 7} N$

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