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Force F on a particle moving in a straight line varies with distance d as shown in the figure. The work done on the particle during its displacement of 12 m is

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21 J

18 J

13 J

26 J

answer is C.

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Detailed Solution

Work done = Area under (,F - x) graph

= 2 $\times (7 - 3) + \frac{1}{2} \times 2 \times (12 - 7)$

= $8 + \frac{1}{2} \times 10 = 8 + 6 = 13 J$

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