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Forces of 100 N each are applied in opposite direction on the upper and lower faces of a cube of side 20 cm. The upper face is shifted parallel to itself by 0.25 cm. If the side of the cube were 10 cm, then the displacement would be

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0.25 cm

0.5 cm

0.75 cm

1 cm

answer is B.

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Detailed Solution

$η = \frac{Fl}{A ∆ l} = \frac{Fl}{l^{2} ∆ l} or ∆ l \infty \frac{1}{l}$

If l is havled, then $∆ l$ is doubled.

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