For H2SO4,the value of Ka2 is 1.×10-6. The concentration of SO4-2 in 0,01M H2SO4 is

HSO4-⇌H++SO4-2 0.01 0.01Ka2=10-6C α2=10-6α =10-6C=10-610-2∴C α =10-4α =10-2

For H2SO4,the value of Ka2 is 1.×10-6. The concentration of SO4-2 in 0,01M H2SO4 is

HSO4-⇌H++SO4-2 0.01 0.01Ka2=10-6C α2=10-6α =10-6C=10-610-2∴C α =10-4α =10-2

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For $H_{2} {SO}_{4},$ the value of ${Ka}_{2} is$ $1 . \times 10^{- 6} .$ The concentration of ${SO}_{4}^{- 2}$ in $0, 01 M H_{2} {SO}_{4} is$

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$1 \times 10^{- 2}$

$1.0 \times 10^{- 6}$

$0.01 \times 10^{- 10}$

$1.0 \times 10^{- 4}$

answer is B.

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Detailed Solution

${HSO}_{4}^{-} ⇌ H^{+} + {SO}_{4}^{- 2}$

0.01 0.01

$K_{a_{2}} = 10^{- 6} C α^{2} = 10^{- 6}$

$α = \sqrt{\frac{10^{- 6}}{C} =} \sqrt{\frac{10^{- 6}}{10^{- 2}}}$

$∴ C α = 10^{- 4}$

$α = 10^{- 2}$

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For H2SO4,the value of Ka2 is 1.×10-6. The concentration of SO4-2 in 0,01M H2SO4 is

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For $H_{2} {SO}_{4},$ the value of ${Ka}_{2} is$ $1 . \times 10^{- 6} .$ The concentration of ${SO}_{4}^{- 2}$ in $0, 01 M H_{2} {SO}_{4} is$