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Q.

Formula of chromic acid is $H_{2} {CrO}_{4}$ . Formula of divalent metal chromate is

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a

{MCrO}_{4}

b

M_{2} {CrO}_{4}

c

M_{3} {CrO}_{4}

d

M_{2} {({CrO}_{4})}_{3}

answer is A.

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Detailed Solution

Both metal and chromate are divalent.

$M_{2} ({CrO}_{4}) \to {2M}^{+} + {CrO}_{4}^{-2}$

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