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Formula of nickel oxide with metal deficiency defect in its crystal is ${Ni}_{0.98} O$ . The crystal contains ${Ni}^{2 +}$ and ${Ni}^{3 +}$ ions. The fraction of nickel existing as ${Ni}^{2 +}$ ions in the crystal is

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0.50

0.96

0.04

0.31

answer is B.

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Detailed Solution

${Ni}_{0.98} O = {({Ni}^{2 +})}_{x} {({Ni}^{3 +})}_{0.98 - x} {(O^{2 -})}_{1} Net charge = 0 [x \times 2] + [(0.98 - x) \times 3] + [- 2 \times 1] = 0 x = 0.94 Fraction of nickel existing as {Ni}^{2 +} = \frac{0.94}{0.98} = 0.959 \approx 0.96$

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