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Q.

For $N_{2} + O_{2} \to 2 NO$ initially $N_{2} & O_{2}$ are at pressures 500mm & 700 mm at t = 0. If the pressure of N₂ is 480 mm at t = 20 min average rate of reaction is (in mm - min^–1)

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a

5

b

1

c

2

d

4

answer is B.

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Detailed Solution

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$\overset{500}{N_{2}} + \overset{700}{O_{2}} \to 2 NO$

change in pressure = 500 - 480 =20

Average rate = $\frac{change in pressure}{time}$

Average rate = $\frac{20}{20} = 1$

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