Q.

For N2O5  in CCl42NO2+12O2K=6×10-4 s-1 at 350 K and K=1.2×10-3 s-1 at 360 K. Then, when temperature is changed to380 K, value of K (in s-1 )

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a

2.4×10-3

b

1.2×10-3

c

4.8×10-3

answer is D.

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Detailed Solution

The given reaction is:

         N2O5 (in CCl42NO2+12O2,

Given the value of K at 350 K is K=6×10-4 s-1 and at 360 K the value is K=1.2×10-3 s-1.

As we know that on increasing the temperature of 10oC, the rate of reaction will be doubled.

So, at 370 K the value of K will be 2.4×10-3 s-1.

At 380 K the value of K will be 4.8×10-3 s-1.

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