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For $N^{3 -} > O^{2 -} > F^{-}$ and ${Na}^{+},$ the order in which their ionic radii varies is

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$N^{- 3} > O^{2 -} > F^{-} > {Na}^{+}$

$N^{- 3} > {Na}^{+} > O^{- 2} > F^{-}$

${Na}^{+} > O^{2 -} > N^{3 -} > F^{-}$

$O^{2 -} > F^{-} > {Na}^{+} > N^{3 -}$

answer is A.

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Detailed Solution

$N^{3 -}, O^{2 -}, F^{-}$ and ${Na}^{+}$ are all isoelectronic species. As the atomic number increases, nuclear attraction increases, hence the order of ionic radii.

$N^{- 3} > O^{2 -} > F^{-} > {Na}^{+}$

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