For ${SO}_{2} {Cl}_{2 (g)} \to {SO}_{2 (g)} + {Cl}_{2 (g)}$ , Pressure of ${SO}_{2} {Cl}_{2}$ changed from 5 atm to 4 atm in 10 min. Then, pressure of ${SO}_{2} {Cl}_{2}$ at the end of 30 minutes will be (in atm)

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5.56

2.56

3.56

4.56

answer is A.

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Detailed Solution

${SO}_{2} {Cl}_{2 (g)} \to {SO}_{2 (g)} + {Cl}_{2 (g)}$ is a first order reaction

For any first order reaction rate constants are same

$k = \frac{2.303}{t} \log \frac{p_{0}}{p}$

$\frac{2.303}{10} \log \frac{5}{4} = \frac{2.303}{30} \log \frac{5}{p}$

p = 2.56 atm

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