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Q.

For z if the minimum value of (|z32|+|zp2i|) is 52, then a value of p is _____________

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a

92

b

72

c

3

d

4

answer is C.

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Detailed Solution

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Question Image
 It is sum of distance of z from (32,0) and (0,p2)
 For minimising, z should lie on AB and AB=52
(AB)2=18+2p218+2p2=50 p=±4

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