For $\mathrm{z}\in \mathrm{ℂ}$ if the minimum value of $\left(\right|\mathrm{z}-3\sqrt{2}|+|\mathrm{z}-\mathrm{p}\sqrt{2}\mathrm{i}\left|\right)\text{ is }5\sqrt{2}$, then a value of p is _____________

$\text{ It is sum of distance of }z\text{ from }(3\sqrt{2},0)\text{ and }(0,p\sqrt{2})$
$\text{ For minimising, }z\text{ should lie on }AB\text{ and }AB=5\sqrt{2}$
$\begin{array}{l}(AB{)}^2=18+2p^2\Rightarrow 18+2p^2=50\\ \\ \Rightarrow p=\pm 4\end{array}$