Four boys and four girls sit in a row randomly. The probability that the four girls sit together is

$\text{E}=$  is an event in which four girls sit together

$\text{G}\text{G}\text{G}\text{G}\text{B}\text{B}\text{B}\text{B}$

$\Rightarrow n\left(\text{E}\right)=5!\times 4!$

$P\left(\text{E}\right)=\frac{n\left(\text{E}\right)}{n\left(\text{S}\right)}$

$=\frac{5!\times 4!\times 3!\times 2!\times 1!}{8!\times 7!\times 6!\times 5!}=\frac{1}{14}$