Four capacitors are connected as shown in fig. Calculate the equivalent capacitance between the points X and Y. 

Clearly, the first plate of $2\mu F$ capacitor, the second plate of $3\mu F$ capacitor are connected and the first plate of $5\mu F$ capacitor are connected to the point A. On the other hand, the second plate of $2\mu F$ capacitor, the first plate of $3\mu F$capacitor and the second plate of $5\mu F$ capacitor are connected and the point B. Thus the capacitors of $2\mu F$, $3\mu F$ and  $5\mu F$ are connected in parallel between points A and B, as shown in the equivalent circuit diagram. Total capacitance of the parallel combination of capacitances  $2\mu F$,$3\mu F$ and $5\mu F$ is 
$C=2+3+5=10\mu F$
Equivalent capacitance between X and Y.
$=\frac{10\times 10}{10+10}=5\mu F$