Four capacitors of capacity 3µF are connected as shown in figure. The ratio of equivalent capacitance between A and B and between A and C will be

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3 : 2

3 : 4

2 : 3

4 : 3

answer is A.

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Detailed Solution

$\begin{array}{l} C_{AB} = \frac{C}{3} parallel to C = \frac{4 C}{3} \\ C_{AC} = \frac{C}{2} parallel to \frac{C}{2} = C; \frac{C_{AB}}{C_{AC}} = \frac{4}{3} \end{array}$

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