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Q.

Four capacitors of equal capacitance have an equivalent capacitance C₁ when connected in series and an equivalent capacitance C₂ when connected in parallel. The ratio $\frac{C_{1}}{C_{2}}$ is

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a

$\frac{1}{16}$

b

$\frac{1}{8}$

c

$\frac{1}{12}$

d

$\frac{1}{4}$

answer is B.

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Detailed Solution

$\begin{array}{rcl} C_{1} & = & \frac{C}{4} \\ C_{2} & = & 4 C \\ \frac{C_{1}}{C_{2}} & = & \frac{1}{16} \end{array}$

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