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Q.

Four devices of power 500 W each used for 10 hours, then the energy used in kWh is

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a

20

b

50

c

5000

d

1.46

answer is A.

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Detailed Solution

$power p = 500W$

$power of 4 devices = 500 \times 4 = 2000 W = 2kW$

$time t = 10hr$

$p = \frac{W}{t} \Rightarrow W = p \times t = 2 \times 10 = 20$

$W = 20 kWh$

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