Q.

Four distinct points (2k, 3k), (1, 0), (0, 1) and  (0, 0) lie on a circle for 

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a

for two values of k 

b

k < 0  

c

0 < k < l  

d

 all integral values of k

answer is D.

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Detailed Solution

The equation of the circle passing through the point (1, 0), (0, 1) and (0, 0) is x2+y2xy=0

This passes through (2k ,3k) 

4k2+9k22k3k=0k=0,k=5/13 

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