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Q.

Four grams of graphite is burnt in bomb calorimeter of heat capacity 30 KJ K-1 in excess of Oxygen at 1 atm pressure. The temperature rises from 300 to 304 K. The heat of reaction at constant volume in KJ/mole is 

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a

– 720

b

 – 400

c

– 1440

d

– 360

answer is B.

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Detailed Solution

Δ U=− Z×θ×Mm
−30×4×124=−360 KJ/mole

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