Four identical capacitors each rates as 10µF – 10V are supplied to you to obtain capacitor of 10µF – 20 V, we should connect them in

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four rows each containing 1 condenser

one row containing four condensers

all the above

two rows each containing 2 condensers

answer is A.

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Detailed Solution

Number of capacitors in a row $= \frac{20}{10} = 2$
Capacity of 1 row $= \frac{10}{2} = 5 μF$
Number of rows $= \frac{10}{5} = 2$
$∴$ two rows, each containing 2 capacitors

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