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Q.

Four identical charges Q are fixed at the four corners of a square of side a. The electric field at a point P located symmetrically at a distance $a / \sqrt{2}$ from the centre of the square is

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a

$\frac{Q}{\sqrt{2} π ε_{0} a^{2}}$

b

$\frac{2 \sqrt{2} Q}{π ε_{0} a^{2}}$

c

$\frac{Q}{2 \sqrt{2} π ε_{0} a^{2}}$

d

$\frac{\sqrt{2} Q}{π ε_{0} a^{2}}$

answer is B.

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Detailed Solution

Question Image

$E_{n e t} = 4 E \cos θ = \frac{4}{4 π ε_{0}} \frac{Q}{a^{2}} \frac{1}{\sqrt{2}} = \frac{Q}{\sqrt{2} π ε_{0} a^{2}}$

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